27w^2=18w

Solution for 27w^2=18w equation:

27w^2=18w

We move all terms to the left:

27w^2-(18w)=0

a = 27; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·27·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*27}=\frac{0}{54}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*27}=\frac{36}{54}
=2/3
$